CSIR UGC NET 2024 December Registration Closes Today: Check Steps To Apply And, Documents Required

The National Testing Agency (NTA) is closing the registration window for the Council of Scientific and Industrial Research-University Grants Commission National Eligibility Test (CSIR-UGC NET) 2024 today, December 30, according to a Times Now report. Eligible candidates who are interested in applying for the exam should complete the registration process online at the official website, csirnet.nta.ac.in, before the deadline.

The CSIR-UGC NET exam is scheduled to take place from February 16 to 28, 2025. The exam will be available in both English and Hindi, allowing candidates to choose their preferred language while filling out the application form. This flexibility aims to ensure a more accessible experience for all candidates.

Once the registration window closes, the NTA will open a correction window from December 31, 2024, to January 2, 2025. During this time, candidates can make necessary changes to their submitted applications, such as correcting personal details or re-uploading documents.

CSIR UGC NET 2024 Registration: Documents Required

To complete the registration process, candidates will need the following documents:

1. Passport-size Photograph
2. Signature
3. Photo ID Proof
4. Birth Certificate
5. Educational Qualification Certificates
6. Caste/Category Certificate (if applicable)
7. Disability Certificate (if applicable)

CSIR UGC NET 2024 Registration: Steps To Apply

1. Visit the official website, csirnet.nta.ac.in.
2. Click on the "CSIR UGC NET December 2024 Registration" link.
3. Register by providing the required personal details.
4. Log in with your credentials and fill out the application form.
5. Upload the necessary documents, including your photograph and signature.
6. Pay the application fee via the available online methods.
7. Save and download the confirmation page for future reference.

Candidates are encouraged to visit the official website for more details and to ensure all information is provided accurately.